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Often, if you have a number of optional parameters, such as in our closure samples, you will want to pass a configuration object rather than separate parameters. Doing so prevents your having to pass "" or some other falsy value parameters prior to the one you want to explicitly pass as in the following sample: var ChocolateChocolate = function () { var _bittersweet = "Ghirardelli", _cocoa = "Callebaut", _vanilla = "Madagascar Bourbon"; return function (bittersweet, cocoa, vanilla) { this.bittersweet = [1, "cup", bittersweet || _bittersweet]; this.cocoa = [3, "tbs", cocoa || _cocoa]; this.vanilla = [1, "bean", vanilla || _vanilla]; }; }(); ChocolateChocolate.prototype = { heavyCream: [1, "cup", "Organic Valley"], halfHalf: [1, "cup", "Organic Valley"], sugar: [5/8, "cup"], yolks: [6] }; var chocolateChocolate = new ChocolateChocolate("", "", "Tahitian"); console.dir(chocolateChocolate); So here s how we can remedy that bugaboo by defining one parameter named pref. As Figure 6 19 displays, this prevents our having to pass empty strings for bittersweet and cocoa in order to pass Tahitian for vanilla.

Figure 9-11. If a duplicate label is found in the second record, it is dropped from the resulting record.

int myNumber0, myNumber1, ..., myNumber99;

Concatenating two lists results in a single list containing the items of the left operand followed by the items of the right operand, as shown in Figure 9-12.

myNumber0 = 0; myNumber1 = 0; . . . myNumber99 = 0;

Figure 9-12. Two lists being concatenated If one or more of the lists items are lists themselves, these lists will remain intact and will not become part of the main list. Figure 9-13 contains two lists. The items of the two lists are themselves lists, but they don t merge with the main list. The left operand is a two-item list, and the right operand is a one-item list; therefore, the result is a three-item list.

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Note that the dots in this last chunk of code are not valid C syntax. They are there to save my fingers some typing. It would take 100 lines of code just to initialize these variables! By using an array, we ve accomplished the same thing in just a few lines of code. Look at this code fragment:

var ChocolateChocolate = function () { var _bittersweet = "Ghirardelli", _cocoa = "Callebaut", _vanilla = "Madagascar Bourbon"; return function (pref) { pref || (pref = {}); this.bittersweet = [1, "cup", pref.bittersweet || _bittersweet]; this.cocoa = [3, "tbs", pref.cocoa || _cocoa]; this.vanilla = [1, "bean", pref.vanilla || _vanilla]; }; }(); ChocolateChocolate.prototype = { heavyCream: [1, "cup", "Organic Valley"], halfHalf: [1, "cup", "Organic Valley"], sugar: [5/8, "cup"], yolks: [6] }; var chocolateChocolate = new ChocolateChocolate({vanilla: "Tahitian"}); console.dir(chocolateChocolate);

Figure 9-13. Only the two main lists combine into a single list when concatenating. List items that are lists remain intact.

sum = 0; for ( i=0; i<100; i++ ) sum += myNumber[ i ]; printf( "The sum of the 100 numbers is %d.", sum );

As a little example of list concatenation, Script 9-2 shows a subroutine that adds a given item to a given list at a given position. The parameters are, as mentioned earlier, the list you want to add to, the item you want to add, and the position. The result is a new list that contains all the items from the original list plus the new item.

In the preceding example, the for loop is used to step through an array, performing some operation on each of the array s elements. You ll use this technique frequently in your own C programs.

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